9a^2-60a+10=0

Solution for 9a^2-60a+10=0 equation:

9a^2-60a+10=0

a = 9; b = -60; c = +10;
Δ = b2-4ac
Δ = -602-4·9·10
Δ = 3240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3240}=\sqrt{324*10}=\sqrt{324}*\sqrt{10}=18\sqrt{10}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-18\sqrt{10}}{2*9}=\frac{60-18\sqrt{10}}{18}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+18\sqrt{10}}{2*9}=\frac{60+18\sqrt{10}}{18}
$